Regex for route matching in Express


Question

I'm not very good with regular expressions, so I want to make sure I'm doing this correctly. Let's say I have two very similar routes, /discussion/:slug/ and /page/:slug/. I want to create a route that matches both these pages.

app.get('/[discussion|page]/:slug', function(req, res, next) {
  ...enter code here...
})

Is this the correct way to do it? Right now I'm just creating two separate routes.

someFunction = function(req, res, next) {..}
app.get('/discussion/:slug', someFunction)
app.get('/page/:slug', someFunction)
1
64
11/4/2013 8:07:50 PM

Accepted Answer

app.get('/:type(discussion|page)/:id', ...) works

107
12/2/2012 12:48:04 AM

You should use a literal javascript regular expression object, not a string, and @sarnold is correct that you want parens for alternation. Square brackets are for character classes.

const express = require("express");
const app = express.createServer();
app.get(/^\/(discussion|page)\/(.+)/, function (req, res, next) {
  res.write(req.params[0]); //This has "discussion" or "page"
  res.write(req.params[1]); //This has the slug
  res.end();
});

app.listen(9060);

The (.+) means a slug of at least 1 character must be present or this route will not match. Use (.*) if you want it to match an empty slug as well.


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